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Khan Academy practice test #5: no calculator Q10, answer is B. I understand how to simplify to 4(a^2+2ab+b^2) but nothing past that. : r/Sat
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a - b)^2 = a^2 - 2ab + b^2 – GeoGebra
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using the formula (a-b)2=(a2-2ab+b2),evaluate (196)2, (689)2 ,(891)2 - Maths - Linear Equations in Two Variables - 14395159 | Meritnation.com
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![Solved 2 -3 A= =C3 :] B = 1 -2 calculate (1) A2 + 2AB + B2, | Chegg.com](https://media.cheggcdn.com/study/d68/d68dcf4d-f7f3-4fa4-b931-f445836f8733/image "Solved 2 -3 A= =C3 :] B = 1 -2 calculate (1) A2 + 2AB + B2, | Chegg.com")
Solved 2 -3 A= =C3 :] B = 1 -2 calculate (1) A2 + 2AB + B2, | Chegg.com
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Was doing cosine law with an sss triangle. I keep getting error on my ti-84 but it works fine on an online calculator. What is causing this? Thanks. : r/trigonometry
a^2+2ab+b^2=25, find a+b - Brainly.in
